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BITSAT2024MathematicsSequences and SeriesActual

There are four numbers of which the first three are in GP and the last three are in AP, whose common difference is 6 . If the first and the last numbers are equal, then two other numbers are

Options

  1. A-2,4
  2. B-4,2
  3. C2,6
  4. DNone of the above

Correct answer

B. -4,2

Step-by-step solution

Let 3 numbers in AP are a,(a+6),(a+12) Also, first and last number out of 4 numbers are equal 4 numbers are (a+12), a,(a+6),(a+12) Also, given, first 3 numbers are in GP array ll & a^2=(a+12)(a+6) & a^2=a^2+18 a+72 & a=- 72 18 =-4 array 4 numbers are 8,-4,2,8

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