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BITSAT 2024Paper 1
Exam
BITSAT
Year
2024
Paper
Paper 1
Subject
Mathematics
Chapter
Sets and Relations

BITSAT 2024 · Paper 1 · Mathematics · Sets and Relations

In an examination, 62 \% of the candidates failed in English, 42%...

In an examination, 62%62 \% of the candidates failed in English, 42% in Mathematics and 20% in both. The number of those who passed in both the subjects isIn an examination, 62 \% of the candidates failed in English, 42% in Mathematics and 20% in both. The number of those

Options

  1. A1111
  2. B1616
  3. C1818
  4. DNone of these

Correct answer

B. 1616

Step-by-step solution

In an examination, 62 \% of the candidates failed in English, 42% in Mathematics and 20% in both. The number of those From the given condition, a+c=62k;b+c=42k\mathrm{a}+\mathrm{c}=62 \mathrm{k} ; \mathrm{b}+\mathrm{c}=42 \mathrm{k} and c=20k\mathrm{c}=20 \mathrm{k} Hence a=42k\mathrm{a}=42 \mathrm{k} and b=22k\mathrm{b}=22 \mathrm{k} Number of students who failed in none means passed in both =n=100k−(a+b+c)=100k−(42k+22k+20k)=16k=\mathrm{n}=100 \mathrm{k}-(\mathrm{a}+\mathrm{b}+\mathrm{c})=100 \mathrm{k}-(42 \mathrm{k}+22 \mathrm{k}+20 \mathrm{k})=16 \mathrm{k}. or 16%16 \%
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