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BITSAT Sets and Relations PYQs with Solutions

20 previous year questions from Sets and Relations (BITSAT Mathematics) with answers and solutions. Numbered list, year tags, and one-tap solutions — built for serious JEE / NEET practice.

20 questionsMathematics2009–2024Answers + solutions

About Sets and Relations PYQs

Sets and Relations has 20 previous year questions in the Quantrex Academy BITSAT Mathematics bank. The 20 questions in this list come from BITSAT (20), spanning 2009 to 2024. Each question opens on its own page with the options, the correct answer and the worked solution where available.

Questions by year (this list)

2024: 4
2023: 2
2022: 1
2020: 1
2017: 2
2016: 1
2015: 2
2014: 2
2013: 2
2012: 1
2010: 1
2009: 1

Sets and Relations questions with solutions

In a statistical investigation of 1003 families of Calcutta, it was found that 63 families has neither a radio nor a TV, 794 families has a radio and 187 has TV. The number of

BITSAT 2024 Solution View → 2

Let R be the relation "is congruent to" on the set of all triangles in a plane is

BITSAT 2024 Solution View → 3

Number of subsets of set of letter of word 'MONOTONE'.

BITSAT 2024 Solution View → 4

In an examination, 62 \% of the candidates failed in English, 42% in Mathematics and 20% in both. The number of those who passed in both the subjects is

BITSAT 2024 Solution View → 5

If n( A)=1000, n( B)=500 and if n( A ∩ B) ≥ 1 and n( A ∪ B)=p , then

BITSAT 2023 Solution View → 6

A set A has 3 elements and another set B has 6 elements. Then

BITSAT 2023 Solution View → 7

If A=\ x: x is a multiple of 4 \ and, B=\ x: x is a multiple of 6 \ , then A ∩ B consists of multiples of

BITSAT 2022 Solution View → 8

In a statistical investigation of 1003 families of Calcutta, it was found that 63 families has neither a radio nor a T.V, 794 families has a radio and 187 has T.V. The number of

BITSAT 2020 Solution View → 9

Let A = 1, 2, 3, 4, 5 and R be a relation defined by R = ( x, y ) : x, y ∈ A, x + y = 5 . Then, R is

BITSAT 2017 Solution View → 10

Let A and B be two sets such that A ∩ X = B ∩ X = ϕ and A ∪ X = B ∪ X for same set X . Then,

BITSAT 2017 Solution View → 11

Two finite sets have m and n elements. The number of subsets of the first set is 112 more than that of the second set. The values of m and n respectively are,

BITSAT 2016 Solution View → 12

Universal set, U=\ x x^ 5 -6 x^ 4 +11 x^ 3 -6 x^ 2 =0\ A=\ x x^ 2 -5 x+6=0\ B=\ x ^ 2 -3x+2=0\ What is (A ∩ B)^ equal to ?

BITSAT 2015 Solution View → 13

If ρ=\ (x, y) x^ 2 +y^ 2 =1 ; x, y ∈ ℝ\ . Then, ρ is

BITSAT 2015 Solution View → 14

The set (A B) ∪(B A) is equal to]

BITSAT 2014 Solution View → 15

Let R=\ (3,3),(6,6),(9,9),(12,12),(6,12), (3,9),(3,12),(3,6) be a relation on the set A=\ 3,6,9,12\ . Then, the relation is

BITSAT 2014 Solution View → 16

A class has 175 students. The following data shows the number of students obtaining one or more subjects. Mathematics 100 , Physics 70 , Chemistry 40; Mathematics and Physics 30

BITSAT 2013 Solution View → 17

Let R be the relation on the set R of all real numbers, defined by a R b If |a-b| ≤ 1 . Then, R is

BITSAT 2013 Solution View → 18

Let A and B be two sets then ( A ∪ B ) ∪ (A^ ∩ B) is equal to

BITSAT 2012 Solution View → 19

Let \( A= \ x: x ∈ R,| x| 1\ \); \( B= \ x: x ∈ R,| x-1| ≥ 1\ and A ∪ B=R-D , then the set \( D is

BITSAT 2010 Solution View → 20

If \(A=\ 1,2,3,4,5\ \), then the number of proper subsets of \(A\) is

BITSAT 2009 Solution View →

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Related BITSAT Mathematics chapters

Application of Derivatives (67)Sequences and Series (51)Probability (44)Three Dimensional Geometry (40)Functions (39)Binomial Theorem (34)Permutation and Combination (31)Complex Number (30)Circle (27)Differential Equations (27)Straight Lines (27)Vector Algebra (25)

Sets and Relations in other exams

JEE Sets and Relations (242)