BITSAT 2015
Exam BITSAT
Year 2015
Subject Mathematics
Chapter Sets and Relations BITSAT 2015 · Mathematics · Sets and Relations
Universal set, U=\ x x^ 5 -6 x^ 4 +11 x^ 3 -6 x^ 2 =0\ A=\ x x^ 2...
Universal set,
U = { x ∣ x 5 − 6 x 4 + 11 x 3 − 6 x 2 = 0 } A = { x ∣ x 2 − 5 x + 6 = 0 } B = { x ∣ \mathrmx 2 − 3 x + 2 = 0 } U=\left\{x \mid x^{5}-6 x^{4}+11 x^{3}-6 x^{2}=0\right\}A=\left\{x \mid x^{2}-5 x+6=0\right\}\mathrm{B}=\left\{\mathrm{x} \mid \mathrmx^{2}-3\mathrm{x}+2=0\right\} U = { x ∣ x 5 − 6 x 4 + 11 x 3 − 6 x 2 = 0 } A = { x ∣ x 2 − 5 x + 6 = 0 } B = { x ∣ \mathrmx 2 − 3 x + 2 = 0 } What is
( A ∩ B ) ′ (A \cap B)^{\prime} ( A ∩ B ) ′ equal to ?
Options A {1,3} B {1,2,3} C {0,1,3} D {0,1,2,3}
Step-by-step solution
U = { x : x 5 − 6 x 4 + 11 x 3 − 6 x 2 = 0 } U=\left\{x: x^{5}-6 x^{4}+11 x^{3}-6 x^{2}=0\right\} U = { x : x 5 − 6 x 4 + 11 x 3 − 6 x 2 = 0 } Solving for values of
x x x , we get
U = { 0 , 1 , 2 , 3 } A = { x : \mathrmx 2 − 5 x + 6 = 0 } \mathrm{U}=\{0,1,2,3\}\mathrm{A}=\left\{\mathrm{x}: \mathrmx^{2}-5 \mathrm{x}+6=0\right\} U = { 0 , 1 , 2 , 3 } A = { x : \mathrmx 2 − 5 x + 6 = 0 } Solving for values of
x x x , we get
A = { 2 , 3 } \mathrm{A}=\{2,3\} A = { 2 , 3 } and
B = { x : \mathrmx 2 − 3 x + 2 = 0 } \mathrm{B}=\left\{\mathrm{x}: \mathrmx^{2}-3 \mathrm{x}+2=0\right\} B = { x : \mathrmx 2 − 3 x + 2 = 0 } Solving for values of
x x x , we get
B = { 2 , 1 } A ∩ B = { 2 } ∴ ( A ∩ B ) ′ = U − ( A ∩ B ) = { 0 , 1 , 2 , 3 } − { 2 } = { 0 , 1 , 3 } \mathrm{B}=\{2,1\}A \cap B=\{2\}\therefore(A \cap B)^{\prime}=U-(A \cap B)=\{0,1,2,3\}-\{2\}=\{0,1,3\} B = { 2 , 1 } A ∩ B = { 2 } ∴ ( A ∩ B ) ′ = U − ( A ∩ B ) = { 0 , 1 , 2 , 3 } − { 2 } = { 0 , 1 , 3 }
Practice Sets and Relations on Quantrex Academy →
← Previous question Two finite sets have m and n elements. The number of subsets of the first set is 112 more…Next question → If ρ=\ (x, y) x^ 2 +y^ 2 =1 ; x, y ∈ ℝ\ . Then, ρ is
More from Sets and Relations
In a statistical investigation of 1003 families of Calcutta, it was found that 63… BITSAT 2024 Let R be the relation "is congruent to" on the set of all triangles in a plane is BITSAT 2024 Number of subsets of set of letter of word 'MONOTONE'. BITSAT 2024 In an examination, 62 \% of the candidates failed in English, 42% in Mathematics and 20%… BITSAT 2024 If n( A)=1000, n( B)=500 and if n( A B) ≥ 1 and n( A B)=p , then BITSAT 2023 A set A has 3 elements and another set B has 6 elements. Then BITSAT 2023 If A=\ x: x is a multiple of 4 \ and, B=\ x: x is a multiple of 6 \ , then A B consists… BITSAT 2022 In a statistical investigation of 1003 families of Calcutta, it was found that 63… BITSAT 2020 Let A = 1, 2, 3, 4, 5 and R be a relation defined by R = ( x, y ) : x, y ∈ A, x + y = 5 .… BITSAT 2017 Let A and B be two sets such that A X = B X = ϕ and A X = B X for same set X . Then, BITSAT 2017 Two finite sets have m and n elements. The number of subsets of the first set is 112 more… BITSAT 2016 If ρ=\ (x, y) x^ 2 +y^ 2 =1 ; x, y ∈ ℝ\ . Then, ρ is BITSAT 2015 The set (A B) (B A) is equal to] BITSAT 2014 Let R=\ (3,3),(6,6),(9,9),(12,12),(6,12), (3,9),(3,12),(3,6) be a relation on the set A=\… BITSAT 2014 A class has 175 students. The following data shows the number of students obtaining one… BITSAT 2013 Let R be the relation on the set R of all real numbers, defined by a R b If |a-b| ≤ 1 .… BITSAT 2013
Full Sets and Relations list
Sets and Relations JEE Maths PYQs JEE Mathematics PYQs
All BITSAT PYQs
