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BITSAT2015MathematicsSets and RelationsActual

If = (x, y) x²+y²=1 ; x, y R . Then, is

Options

  1. Areflexive
  2. Bsymmetric
  3. Ctransitive
  4. Danti-symmetric

Correct answer

B. symmetric

Step-by-step solution

Obviously, the relation is not reflexive and transitive, but it is symmetric, because x²+x²=2 x² 1 array l and x²+y²=1, y²+z²=1 x²+z²=1 But x²+y²=1 y²+x²=1 array

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