Voltage V and current i in A C circuit are given by V =50 (50 t ) volt, i =50 (50 t + 3 ) mA The power dissipated in the circuit is

Step-by-step solution

Given V=50 (50 t) V Maximum voltage, V ₀=50 ~V i= (50 t+ 3 ) mA Maximum current, i₀=50 ~mA =50 10⁻³ ~A Power dissipated, P = i ₀ 2 V ₀ 2 = 50 50 10⁻³ 2 = 2500 10⁻³ 2 =1.25 ~W