Two capacitors C_ 1 and C_ 2 are charged to 120 V and 200 V...

Two capacitors

\mathrm{C}_{1}

and

\mathrm{C}_{2}

are charged to

120 \mathrm{ V}

and

200 \mathrm{ V}

respectively. It is found that by connecting them together the potential on each one can be made zero. Then Two capacitors C_ 1 and C_ 2 are charged to 120 V and 200 V respectively. It is found that by connecting them together

Two capacitors C_ 1 and C_ 2 are charged to 120 V and 200 V respectively. It is found that by connecting them together

Options

A $5 C_{1}=3 C_{2}$
B $3 C_{1}=5 C_{2}$
C $3 C_{1}+5 C_{2}=0$
D $9 C_{1}=4 C_{2}$

Correct answer

B. $3 C_{1}=5 C_{2}$

Step-by-step solution

For potential to be made zero, after connection

120 \mathrm{C}_{1}=200 \mathrm{C}_{2} \quad\left[\because C=\frac{q}{v}\right]\Rightarrow 3 C_{1}=5 C_{2}

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