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BITSAT2010PhysicsCenter of Mass, Momentum and CollisionActual

A spring is compressed between two toy carts of mass m ₁ and m ₂ . When the toy carts are released, the springs exert equal and opposite average forces for the same time on each toy cart. If v₁ and v ₂ are the velocities of the toy carts and there is no friction between the toy carts and the ground, then :

Options

  1. Av ₁ / v ₂= m ₁ / m ₂
  2. Bv ₁ / v ₂= m ₂ / m ₁
  3. Cv ₁ / v ₂=- m ₂ / m ₁
  4. Dv ₁ / v ₂=- m ₁ / m ₂

Correct answer

C. v ₁ / v ₂=- m ₂ / m ₁

Step-by-step solution

Applying law of conservation of linear momentum m ₁ v ₁+ m ₂ v ₂=0 m ₁ ~m ₂ =- v ₂ v ₁ or v ₁ v ₂ =- m ₂ ~m ₁

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