BITSAT2010PhysicsCenter of Mass, Momentum and CollisionActual
A system consists of three particles, each of mass m and located at (1,1),(2,2) and (3,3) . The co-ordinates of the centre of mass are
Options
- A(1,1)
- B(2,2)
- C(3,3)
- D(6,6)
Correct answer
B. (2,2)
Step-by-step solution
The coordinates of C.M of three particle are array c x = m ₁ x ₁+ m ₂ x ₂+ m ₃ x ₃ ~m ₁+ m ₂+ m ₃ & y = m ₁ y ₁+ m ₂ y ₂+ m ₃ y ₃ ~m ₁+ m ₂+ m ₃ here m ₁= m ₂= m ₃= m so x = ( x ₁+ x ₂+ x ₃ ) m m + m + m =2 array y= (y₁+y₂+y₃ ) m m+m+m =2 so coordinates of C . M . of three particle are (2,2) V =300 ~m / s