In the given circuit, E₁=E₂=E₃=2 ~V and R₁=R₂=4 , then current flowing through the branch A B is

Step-by-step solution

The given circuit can be redrawn as, where, equivalent emf of the combination, aligned E_ eq & = E₁ R₁+E₂ R₂ R₁+R₂ & = 2 4+2 4 4+4 =2 ~V aligned and R_ e q = R₁ R₂ R₁+R₂ = 4 4 4+4 = 16 8 =2 Net emf of the circuit, aligned E^ & =E₂+E_ eq & =2+2 & =4 ~V aligned Current flowing through branch A B , I= E^ R_ e q = 4 2 =2 ~A Clearly from figure, it is clear that direction of current is from point A to B clockwise is loop.