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BITSAT 2023Paper 1
Exam
BITSAT
Year
2023
Paper
Paper 1
Subject
Physics
Chapter
Current Electricity

BITSAT 2023 · Paper 1 · Physics · Current Electricity

The resistance of a wire is 5 . It's new resistance in ohm if...

The resistance of a wire is 5Ω5 \Omega. It's new resistance in ohm if stretched to 5 times of its original length will be :The resistance of a wire is 5 . It's new resistance in ohm if stretched to 5 times of its original length will be :

Options

  1. A625
  2. B5
  3. C125
  4. D25

Correct answer

C. 125

Step-by-step solution


The resistance of a wire is 5 . It's new resistance in ohm if stretched to 5 times of its original length will be :

Let resistance of a wire RR and length 1.
R=ρℓA=5Ω\mathrm{R}=\frac{\rho \ell}{\mathrm{A}}=5 \Omega
∴\therefore \quad Volume of wire is constant in stretching
Vi=Vf⇒Aiℓi=AfℓfV_i=V_f \Rightarrow A_i \ell_i=A_f \ell_f
Aℓ=A′(5ℓ)⇒A′=A5\mathrm{A} \ell=\mathrm{A}^{\prime}(5 \ell) \Rightarrow \mathrm{A}^{\prime}=\frac{\mathrm{A}}{5}
Rf=ρℓfAf=ρ(5ℓ)(A5)=25(ρℓA)=25×5=125ΩR_f=\frac{\rho \ell_f}{A_f}=\frac{\rho(5 \ell)}{\left(\frac{A}{5}\right)}=25\left(\frac{\rho \ell}{A}\right)=25 \times 5=125 \Omega
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