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BITSAT 2023Paper 2
Exam
BITSAT
Year
2023
Paper
Paper 2
Subject
Physics
Chapter
Current Electricity

BITSAT 2023 · Paper 2 · Physics · Current Electricity

Ratio of thermal energy released in two resistor R and 3 R...

Ratio of thermal energy released in two resistor RR and 3R3 R connected in parallel in an electric circuit is :

Options

  1. A
    3 : 1
  2. B
    1 : 1
  3. C
    1 : 3
  4. D
    1 : 27

Correct answer

A.
3 : 1

Step-by-step solution

Thermal energy is given by
H=P×t=V2R×t\mathrm{H}=\mathrm{P} \times \mathrm{t}=\frac{\mathrm{V}^2}{\mathrm{R}} \times \mathrm{t}
Here, voltage V\mathrm{V} is same.
∴H1H2=V2tRV2t3R=3:1\therefore \quad \frac{\mathrm{H}_1}{\mathrm{H}_2}=\frac{\frac{\mathrm{V}^2 \mathrm{t}}{\mathrm{R}}}{\frac{\mathrm{V}^2 \mathrm{t}}{3 \mathrm{R}}}=3: 1
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