BITSAT2016PhysicsDual Nature of MatterActual
Find the number of photon emitted per second by a 25 watt source of monochromatic light of wavelength 6600 Å . What is the photoelectric current assuming 3 % efficiency for photoelectric effect?
Options
- A25 3 10¹⁹ ~J , 0.4 amp
- B25 4 10¹⁹ ~J , 6.2 amp
- C25 2 10¹⁹ ~J , 0.8 amp
- DNone of these
Correct answer
A. 25 3 10¹⁹ ~J , 0.4 amp
Step-by-step solution
P_ in =25 ~W , =6600 =6600 10⁻¹⁰ ~m n h v=P Number of photons emitted/sec aligned n &= P h c = P h c = 25 6600 10⁻¹⁰ 6.64 10⁻³⁴ 3 10⁸ &=8.28 10¹⁹= 25 3 10¹⁹ aligned 3 % of emitted photons are producing current aligned & I= 3 100 n e &= 3 100 25 3 10¹⁹ 1.6 10⁻¹⁹=0.4 ~A aligned