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BITSAT2014PhysicsElectromagnetic InductionActual

A coil 10 turns and a resistance of 20 is connected in series with B.G of resistance 30 . The coil is placed with its plane perpendicular to the direction of a uniform magnetic field of induction 10⁻² ~T . If it is now turned through an angle of 60^ about an axis in its plane. Find the charge induced in the coil. (Area of a coil =10⁻² ~m ² )

Options

  1. A2 10⁻⁵ C
  2. B3.2 10⁻⁵ C
  3. C1 10⁻⁵ C
  4. D5.5 10⁻⁵ C

Correct answer

C. 1 10⁻⁵ C

Step-by-step solution

Given: n =10 turns, R _ coil =20 , R _ G =30 , Total resistance in the circuit =20+30=50 A =10⁻² ~m ², ~B =10⁻² ~T , ₁=0^ , ₂=60^ q = ₁- ₂ R = Bn A ₁- Bn A ₂ R = Bn A ( 0- 60) R = BnA (1-0.5) R = 0.5 10⁻² 10 10⁻² 50 = 50 10⁻⁵ 50 =1 10⁻⁵ C (Charge induced in a coil)

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