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BITSAT 2019
Exam
BITSAT
Year
2019
Subject
Physics
Chapter
Electrostatics

BITSAT 2019 · Physics · Electrostatics

In the following figures, which figure represents the variation of...

In the following figures, which figure represents the variation of the electric field with distance from the centre of a uniformly charged non-conducting spheres of radius RR& ?In the following figures, which figure represents the variation of the electric field with distance from the centre ofIn the following figures, which figure represents the variation of the electric field with distance from the centre ofIn the following figures, which figure represents the variation of the electric field with distance from the centre ofIn the following figures, which figure represents the variation of the electric field with distance from the centre of

Options

  1. AThe mean and standard deviation of the marks of 10 students were found to be 50 and 12 respectively. Later, it was
  2. BThe mean and standard deviation of the marks of 10 students were found to be 50 and 12 respectively. Later, it was
  3. CThe mean and standard deviation of the marks of 10 students were found to be 50 and 12 respectively. Later, it was
  4. DThe mean and standard deviation of the marks of 10 students were found to be 50 and 12 respectively. Later, it was

Correct answer

C. The mean and standard deviation of the marks of 10 students were found to be 50 and 12 respectively. Later, it was

Step-by-step solution

The electric field intensity at a point lying outside the sphere (non-conducting) is

E=14πε0⋅qr2E = \dfrac{1}{4\pi{ε}_{0}} \cdot \dfrac{q}{r2}

i.e. E∝1r2…(i)E ∝ \dfrac{1}{r2} \ldots \left(i\right)

The electric field intensity at the surface (r=R)( r = R ),

E=14πε0qR2E = \dfrac{1}{4\pi{ε}_{0}}\dfrac{q}{R2}

⇒E∝1R2⇒ E ∝ \dfrac{1}{R2}

where, RR being the radius of sphere,

The electric field intensity inside the sphere is

E=qr4πε0R3E = \dfrac{qr}{4\pi{ε}_{0}R^{3}}

⇒E∝r⇒ E ∝ r

At the centre of sphere, r=0,∴E=0r = 0, ∴ E = 0

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