BITSAT2012PhysicsElectrostaticsActual
In a region of space having a uniform electric field E , a hemispherical bowl of radius r is placed. The electric flux through the bowl is
Options
- A2 RE
- B4 R² E
- C2 R² E
- DR² E
Correct answer
C. 2 R² E
Step-by-step solution
= E ( ds ) = E (2 r ² ) 0^ =2 r ² E