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BITSAT 2012
Exam
BITSAT
Year
2012
Subject
Physics
Chapter
Electrostatics

BITSAT 2012 · Physics · Electrostatics

In a region of space having a uniform electric field E , a...

In a region of space having a uniform electric field E\mathrm{E}, a hemispherical bowl of radius r\mathrm{r} is placed. The electric flux ϕ\phi through the bowl is

Options

  1. A2πRE2 \pi \mathrm{RE}
  2. B4πR2E4 \pi R^{2} E
  3. C2πR2E2 \pi R^{2} E
  4. DπR2E\pi R^{2} E

Correct answer

C. 2πR2E2 \pi R^{2} E

Step-by-step solution

ϕ=E(ds)cos⁡θ=E(2π\mathrmr2)cos⁡0∘=2π\mathrmr2E\phi=\mathrm{E}(\mathrm{ds}) \cos \theta=\mathrm{E}\left(2 \pi \mathrmr^{2}\right) \cos 0^{{}^{\circ}}=2 \pi \mathrmr^{2} \mathrm{E}
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