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BITSAT 2010
Exam
BITSAT
Year
2010
Subject
Physics
Chapter
Electrostatics

BITSAT 2010 · Physics · Electrostatics

Two metallic spheres of radii 1 cm and 3 cm are given charges of -1...

Two metallic spheres of radii 1cm1 \mathrm{ cm} and 3cm3 \mathrm{ cm} are given charges of −1×10−2C-1 \times 10^{-2} \mathrm{C} and 5×10−2C5 \times 10^{-2} \mathrm{C}, respectively. If these are connected by a conducting wire, the final charge on the bigger sphere is

Options

  1. A2×10−2C2 \times 10^{-2} \mathrm{C}
  2. B3×10−2C3 \times 10^{-2} C
  3. C4×10−2C4 \times 10^{-2} C
  4. D1×10−2C1 \times 10^{-2} C

Correct answer

B. 3×10−2C3 \times 10^{-2} C

Step-by-step solution

kx1cm=k(Q−x)3cm3x=Q−x⇒4x=Qx=Q4=4×10−24C=1×10−2Q′=Q−x=3×10−2C\quad \frac{k x}{1 \mathrm{ cm}}=\frac{k(Q-x)}{3 \mathrm{ cm}}3 x=Q-x \Rightarrow 4 x=Qx=\frac{Q}{4}=\frac{4 \times 10^{-2}}{4} C=1 \times 10^{-2}Q^{\prime}=\mathrm{Q}-x=3 \times 10^{-2} \mathrm{C}
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