BITSAT2019PhysicsMagnetic Effects of CurrentActual
A proton is revolving on a circular path of radius 2 mm with frequency 10 Hz . Magnetic dipole moment associated with proton is
Options
- A2 × 10 - 24   A - m 2
- B4 × 10 - 24   A - m 2
- C3 × 10 - 20   A - m 2
- D6 × 10 - 20   A - m 2
Correct answer
A. 2 × 10 - 24   A - m 2
Step-by-step solution
Given, charge on proton, q = e = 1 . 6 × 10 - 19   C Radius,    r = 2   mm = 2 × 10 - 3   cm Frequency, f = 10   Hz Current associated by proton is given by I = q t [ T → time period ] = q f                                                        ∵ T = 1 f = 1 . 6 × 10 - 19 × 10 = 1 . 6 × 10 - 18   A ∴