A charged particle moving in a uniform magnetic field and losses 4 % of its kinetic energy. The radius of curvature of its path changes by

Step-by-step solution

As we know F = qvB = mv ² r r = mv Bq And KE = k = 1 2 mv ² mv = 2 ~km r = mv qB = 2 ~km qB r k or r=c^ 1 / 2 (c is a constant ) dr dr = c dk ^ 1 / 2 dr or c k r =2 k r r = c k 2 k c k = k 2 k Therefore percentage changes in radius of path, r r 100= k 2 k 100=2 %