A block of wood floats in water with ( 4 / 5 ) th of its volume submerged. If the same block just floate in a liquid, the density of liquid in kg m - 3 is

Step-by-step solution

Let V be the volume of the block. When block floats in water, then V block   g = 4 5 v ρ water   g or P block = 4 5 ρ water           . . . . . i When block floats in liquid. V ρ block   g = V ρ liquid g ρ block   = ρ liquid   ρ liquid   = 4 5 ρ water   [from Eq. (i)] = 4 5 × 10 3   kg   m - 3 = 800   kg   m - 3