An ice-berg of density 900 kgm ^ - 3 is floating in water of...

Let the volume of ice-berg is $V$ and its density is $ρ$. If this ice-berg floats in water with volume ${V}_{in}$ inside it, then

${V}_{in}\sigmag = Vρg$

$\sigma =$ density of water

$⇒ {V}_{in} = \left(\dfrac{ρ}{σ}\right) \cdot V$

$⇒ {V}_{out} = V - {V}_{in}$

$= \left[\dfrac{\sigma - ρ}{σ}\right]V = \dfrac{1000 - 900}{1000}V$

$= \dfrac{V}{10}$

$⇒ {V}_{out} / V = 0. 1 = 10$