Work done in increasing the size of a soap bubble from radius of (3...

Work done in increasing the size of a soap bubble from radius of (3

to 5

)

cm

is nearly (surface tension of soap solution

= 0. 03{Nm}^{- 1}

)

Options

A $0. 2\pimJ$
B $2\pimJ$
C $0. 4\pimJ$
D $4\pimJ$

Correct answer

D. $4\pimJ$

Step-by-step solution

Work done = Change in surface energy

${r}_{2} = 5cm$

${r}_{1} = 3cm$

$⇒ W = 2T \times 4\pi \left({r}_{2}^{2} - {r}_{1}^{2}\right)</p><p>$ = 2 $\times0. 03 \times4\pi\left[ \left(5\right)^{2} - \left(3\right)^{2}\right]\times {10}^{- 4}$

$= 0. 4\pimJ$

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