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BITSAT 2020
Exam
BITSAT
Year
2020
Subject
Physics
Chapter
Motion in Two Dimensions

BITSAT 2020 · Physics · Motion in Two Dimensions

The equation of a projectile is y= 3 x- g x^ 2 2 The angle of...

The equation of a projectile is y=3x−gx22y=\sqrt{3} x-\frac{g x^{2}}{2} The angle of projection is given by

Options

  1. Atan⁡θ=13\tan \theta=\frac{1}{\sqrt{3}}
  2. Btan⁡θ=3\tan \theta=\sqrt{3}
  3. Cπ2\frac{\pi}{2}
  4. Dzero.

Correct answer

B. tan⁡θ=3\tan \theta=\sqrt{3}

Step-by-step solution

Comparing the given equation with y=xtan⁡θ−gx22u2cos⁡2θ, we get tan⁡θ=3\mathrm{y}=\mathrm{x} \tan \theta-\frac{\mathrm{gx}^{2}}{2 \mathrm{u}^{2} \cos ^{2} \theta}, \text{ we get }\tan \theta=\sqrt{3}
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