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BITSAT 2013
Exam
BITSAT
Year
2013
Subject
Physics
Chapter
Motion in Two Dimensions

BITSAT 2013 · Physics · Motion in Two Dimensions

A body is projected, making an acute angle with the horizontal. If...

A body is projected, making an acute angle with the horizontal. If angle between velocity v⃗\vec{v} and acceleration g→\overrightarrow{\mathrm{g}} is θ,\theta, then

Options

  1. Aθ=90∘\theta=90^{{}^{\circ}}
  2. Bθ=0∘\quad \theta=0^{{}^{\circ}}
  3. C90∘<θ<0∘90^{{}^{\circ}}< \theta< 0^{{}^{\circ}}
  4. D0∘<θ<180∘0^{{}^{\circ}}< \theta< 180^{{}^{\circ}}

Correct answer

D. 0∘<θ<180∘0^{{}^{\circ}}< \theta< 180^{{}^{\circ}}

Step-by-step solution

Here velocity is acting upwards when projectile is going upwards and acceleration is downwards. The angle θ\theta between v→\overrightarrow{\mathrm{v}} and  a →\overrightarrow{\text{ a }} is more than 0∘0^{{}^{\circ}} and less than 180∘180^{{}^{\circ}}
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