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BITSAT 2017
Exam
BITSAT
Year
2017
Subject
Physics
Chapter
Oscillations

BITSAT 2017 · Physics · Oscillations

A rectangular block of mass m and area of cross-section A floats in...

A rectangular block of mass mm and area of cross-section AA floats in a liquid of density ρρ. If it is given a vertical displacement from equilibrium, it undergoes oscillation with a time period TT. Then

Options

  1. AT∝ρT ∝ \sqrt{ρ}
  2. BT∝1AT ∝ \dfrac{1}{A}
  3. CT∝1ρT ∝ \dfrac{1}{ρ}
  4. DT∝1mT ∝ \dfrac{1}{m}

Correct answer

B. T∝1AT ∝ \dfrac{1}{A}

Step-by-step solution

Let block is displaced through xmxm, then weight of displaced water or upthrust (upwards)

=−Axρg= - Axρg

Where, AA is area of a cross-section of the block and ρ\rho is density. This must be equal to force (=ma)\left(= ma\right) applied where mm is mass of the block and aa is acceleration.

∴ma=−Axρg∴ ma = - Axρg

or a=−Aρgmx=−ω2xa = - \dfrac{Aρg}{m}x = - {ω}^{2}x

This is equation of SHMSHM.

The time period of oscillation,

T=2πω=2πmAρgT = \dfrac{2\pi}{ω} = 2\pi\sqrt{\dfrac{m}{Aρg}}

⇒T∝1A⇒ T ∝ \dfrac{1}{A}

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