Two simple pendulums of lengths 5m and 20m respectively are given...

Two simple pendulums of lengths

5m

and

20m

respectively are given small displacement in one direction at the same time they will again be in the same sense when the pendulum of shorter length has completed

n

oscillations. Then,

n

Options

A $5$
B $1$
C $2$
D $3$

Correct answer

C. $2$

Step-by-step solution

According to question

${n}_{1}{T}_{1} = {n}_{2}{T}_{2}$

$⇒ n \cdot 2\pi\sqrt{\dfrac{5}{g}} = \left(n - 1\right)^{2}\pi\sqrt{\dfrac{20}{g}}$

$\dfrac{n}{n - 1} = 2 ⇒ n = 2$

Practice Oscillations on Quantrex Academy →

More from Oscillations

Five identical springs are used in the three configurations as shown in figure. The time… BITSAT 2024 A particle executes simple harmonic motion between x=-A and x=+A . If time taken by… BITSAT 2024 A simple pendulum doing small oscillations at a place R height above earth surface has… BITSAT 2024 The variation of kinetic energy (KE) of a particle executing simple harmonic motion with… BITSAT 2023 A particle executes SHM of amplitude A. The distance from the mean position when it's… BITSAT 2023 In a resonance column first and second resonance are obtained at depths 24 cm and 78 cm… BITSAT 2022 Four massless springs whose force constants are 2 k, 2 k, k and 2 k respectively are… BITSAT 2021 In a simple pendulum of length I the bob is pulled aside from its equilibrium position… BITSAT 2021 Full Oscillations list All BITSAT PYQs