BITSAT 2014
- Exam
- BITSAT
- Year
- 2014
- Subject
- Physics
- Chapter
- Oscillations
BITSAT 2014 · Physics · Oscillations
Two particles P and Q describe S.H.M. of same amplitude a, same...
Two particles and describe S.H.M. of same amplitude a, same frequency along the same straight line. The maximum distance between the two particles is . The initial phase difference between the particle is
Options
- Azero
- B
- C
- D
Correct answer
B.
Step-by-step solution
\mathrm{x}_{1}=\mathrm{a} \sin \left(\omega \mathrm{t}+\phi_{1}\right), \mathrm{x}_{2}=\mathrm{a} \sin \left(\omega \mathrm{t}+\phi_{2}\right)\Rightarrow \quad\left|\mathrm{x}_{1}-\mathrm{x}_{2}\right|=2 \mathrm{a} \sin \left(\omega \mathrm{t}+\frac{\phi_{1}+\phi_{2}}{2}\right) \cos \left(\frac{\phi_{1}-\phi_{2}}{2}\right)
Tomaximize \left|\mathrm{x}_{1}-\mathrm{x}_{2}\right|1\Rightarrow 2 1 \times \cos \left(\frac{\phi_{1}-\phi_{2}}{2}\right)\Rightarrow \frac{1}{\sqrt{2}}=\cos \left(\frac{\phi_{1}-\phi_{2}}{2}\right) \Rightarrow \frac{\pi}{4}=\frac{\phi_{1}-\phi_{2}}{2}\Rightarrow \phi_{1}-\phi_{2}=\frac{\pi}{2}$$