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BITSAT 2014
Exam
BITSAT
Year
2014
Subject
Physics
Chapter
Oscillations

BITSAT 2014 · Physics · Oscillations

Two particles P and Q describe S.H.M. of same amplitude a, same...

Two particles P\mathrm{P} and Q\mathrm{Q} describe S.H.M. of same amplitude a, same frequency f\mathrm{f} along the same straight line. The maximum distance between the two particles is a2\mathrm{a} \sqrt{2}. The initial phase difference between the particle is −-

Options

  1. Azero
  2. Bπ/2\pi / 2
  3. Cπ/6\pi / 6
  4. Dπβ\pi \beta

Correct answer

B. π/2\pi / 2

Step-by-step solution

\mathrm{x}_{1}=\mathrm{a} \sin \left(\omega \mathrm{t}+\phi_{1}\right), \mathrm{x}_{2}=\mathrm{a} \sin \left(\omega \mathrm{t}+\phi_{2}\right)\Rightarrow \quad\left|\mathrm{x}_{1}-\mathrm{x}_{2}\right|=2 \mathrm{a} \sin \left(\omega \mathrm{t}+\frac{\phi_{1}+\phi_{2}}{2}\right) \cos \left(\frac{\phi_{1}-\phi_{2}}{2}\right) Tomaximize \left|\mathrm{x}_{1}-\mathrm{x}_{2}\right|:sin⁡(ωt+ϕ1+ϕ22)=: \sin \left(\omega \mathrm{t}+\frac{\phi_{1}+\phi_{2}}{2}\right)=1\Rightarrow a2=\mathrm{a} \sqrt{2}=2 a×\mathrm{a} \times1 \times \cos \left(\frac{\phi_{1}-\phi_{2}}{2}\right)\Rightarrow \frac{1}{\sqrt{2}}=\cos \left(\frac{\phi_{1}-\phi_{2}}{2}\right) \Rightarrow \frac{\pi}{4}=\frac{\phi_{1}-\phi_{2}}{2}\Rightarrow \phi_{1}-\phi_{2}=\frac{\pi}{2}$$
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