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JEE Advanced 2024Paper 2
Exam
JEE Advanced
Year
2024
Paper
Paper 2
Subject
Chemistry
Chapter
Aldehydes and Ketones

JEE Advanced 2024 · Paper 2 · Chemistry · Aldehydes and Ketones

Paragraph I: An organic compound ( P ) with molecular formula ( C _...

Paragraph I: An organic compound (P\mathrm{P}) with molecular formula (\mathrm{C}}_{5} \mathrm{H}_{18} \mathrm{O}}_{2}) decolorizes bromine water and also shows positive iodoform test. (P\mathrm{P}) on ozonolysis followed by treatment with (\mathrm{H}}_{2} \mathrm{O}}_{2}) gives (Q\mathrm{Q}) and (R\mathrm{R}). While compound (Q\mathrm{Q}) shows positive iodoform test, compound (R\mathrm{R}) does not give positive iodoform test. (Q\mathrm{Q}) and (R\mathrm{R}) on oxidation with pyridinium chlorochromate (PCC) followed by heating give (S\mathrm{S}) and (T\mathrm{T}), respectively. Both (S\mathrm{S}) and (T\mathrm{T}) show positive iodoform test. Complete copolymerization of 500 moles of (Q\mathrm{Q}) and 500 moles of (R\mathrm{R}) gives one mole of a single acyclic copolymer (U\mathrm{U}). [Given, atomic mass: (H=\mathrm{H}=1, C=\mathrm{C}=12, O=\mathrm{O}=16)] Question: The molecular weight of U\mathbf{U} isParagraph I: An organic compound ( P ) with molecular formula ( C _ 5 H_ 18 O _ 2 ) decolorizes bromine water and alsoParagraph I: An organic compound ( P ) with molecular formula ( C _ 5 H_ 18 O _ 2 ) decolorizes bromine water and also

Correct answer

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Step-by-step solution

Paragraph I: An organic compound ( P ) with molecular formula ( C _ 5 H_ 18 O _ 2 ) decolorizes bromine water and also S & T\mathrm{S~} \& \mathrm{~T} shows + ve idoform test. RmfC5H10O3\mathrm{Rmf} \mathrm{C}_5 \mathrm{H}_{10} \mathrm{O}_3 (M. wt )R=70+48=118QmfC4H8O3(M.wt)Q=56+48=104)_{\mathrm{R}}=70+48=118 \mathrm{Q} \mathrm{mf} \mathrm{C}_4 \mathrm{H}_8 \mathrm{O}_3(\mathrm{M} . \mathrm{wt})_{\mathrm{Q}}=56+48=104 500 mole Q+500\mathrm{Q}+500 mole R→ polymer  Condensation \mathrm{R} \xrightarrow[\text{ polymer }]{\text{ Condensation }} Paragraph I: An organic compound ( P ) with molecular formula ( C _ 5 H_ 18 O _ 2 ) decolorizes bromine water and also U molecular weight =500×118+500×104−999×18=500×222−17982=111000−17982=93018\begin{aligned} \mathrm{U} \text{ molecular weight } & =500 \times 118+500 \times 104-999 \times 18=500 \times 222-17982 \\ & =111000-17982=93018\end{aligned} Ans. is ⇒93018\Rightarrow 93018
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