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JEE Advanced 2021Paper 1
Exam
JEE Advanced
Year
2021
Paper
Paper 1
Subject
Chemistry
Chapter
Biomolecules

JEE Advanced 2021 · Paper 1 · Chemistry · Biomolecules

Given: The compound (s), which on reaction with HNO _ 3 will give...

Given: Given: The compound (s), which on reaction with HNO _ 3 will give the product having degree of rotation, [α]D = - 52 .7 The compound (s),\left(s\right), which on reaction with HNO3{HNO}_{3} will give the product having degree of rotation, \left[\alpha\right]D = - 52 .7 ° is (are)

Options

  1. AParagraph: Let x=( ^2 A+ A+1)/( A) where 0 Question: At what value of A does x attain the minimum value?
  2. BParagraph: Let x=( ^2 A+ A+1)/( A) where 0 Question: At what value of A does x attain the minimum value?
  3. CParagraph: Let x=( ^2 A+ A+1)/( A) where 0 Question: At what value of A does x attain the minimum value?
  4. DParagraph: Let x=( ^2 A+ A+1)/( A) where 0 Question: At what value of A does x attain the minimum value?

Correct answer

C. Paragraph: Let x=( ^2 A+ A+1)/( A) where 0 Question: At what value of A does x attain the minimum value?

Step-by-step solution

Given: The compound (s), which on reaction with HNO _ 3 will give the product having degree of rotation, [α]D = - 52 .7
Now the structure, that shows [∝]D=−52.7∘[\propto]_{D}=-52.7^{\circ} is
Given: The compound (s), which on reaction with HNO _ 3 will give the product having degree of rotation, [α]D = - 52 .7
Given: The compound (s), which on reaction with HNO _ 3 will give the product having degree of rotation, [α]D = - 52 .7
Given: The compound (s), which on reaction with HNO _ 3 will give the product having degree of rotation, [α]D = - 52 .7
Given: The compound (s), which on reaction with HNO _ 3 will give the product having degree of rotation, [α]D = - 52 .7
Given: The compound (s), which on reaction with HNO _ 3 will give the product having degree of rotation, [α]D = - 52 .7
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