The structure of a peptide is given below. If the absolute values...

The structure of tripeptide will be as followed at $PH = 2$ (in highly acidic medium)

hence \left|{z}_{1}\right| = 2$at$pH = 6$(in approximately neutral solution it will be</p><p><img src="https://cdn-question-pool.Quantrex.app/pyq/jee_advanced/57e644c9-c455-4084-9944-b6589e217c17-image.png"/></p><p>Hence \left|{z}_{2}\right| = 0 pH = 11$ (in highly basic medium) the structure will be

Hence \left|{z}_{3}\right|$will be$3$.</p><p>Therefore \left|{z}_{1}\right| + \left|{z}_{2}\right| + \left|{z}_{3}\right| = 2 + 0 + 3 = 5$.