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JEE Advanced2016ChemistryChemical EquilibriumActual

Paragraph: Thermal decomposition of gaseous X ₂ to gaseous X at 298 ~K takes place according to the following equation: X ₂( ~g ) 2 X ( g ) The standard reaction Gibbs energy, _ r G^ , of this reaction is positive. At the start of the reaction, there is one mole of X ₂ and no X . As the reaction proceeds, the number of moles of X formed is given by . Thus, _ equilibrium is the number of moles of X formed at equilibri

Options

  1. A8 β e q u i l i b r i u m 2 2 - β e q u i l i b r i u m
  2. B8 β e q u i l i b r i u m 2 4 - β e q u i l i b r i u m 2
  3. C4 β e q u i l i b r i u m 2 2 - β e q u i l i b r i u m
  4. D4 β e q u i l i b r i u m 2 4 - β e q u i l i b r i u m 2

Correct answer

B. 8 β e q u i l i b r i u m 2 4 - β e q u i l i b r i u m 2

Step-by-step solution

X 2 ( g ) at     equilibrium ⇌ 2 X ( g ) β equilibrium n T = 1 − β equilibrium 2 + β equilibrium = 1 + β equilibrium 2 1 - β equilibrium 2 K P = P x 2 P x 2 = β equilibrium 1 + β equilibrium 2 P T 2 1 - β equilibrium 2 1 + β equilibrium 2 P T K P = β e q u i l i b r i u m 2 1 - β e q u i l i b r i u m 2 4 P T = 2 β e q u i l i b r i u m 2 1 - β e q u i l i b r i u m 4 = 8 β e q u i l i b r i u m 2 4 - β e q u i l i b

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