JEE Advanced 2018Paper 1
- Exam
- JEE Advanced
- Year
- 2018
- Paper
- Paper 1
- Subject
- Chemistry
- Chapter
- Electrochemistry
JEE Advanced 2018 · Paper 1 · Chemistry · Electrochemistry
For the electrochemical cell, Mg(s)| Mg ^ 2+ (aq,1M)| | Cu ^ 2+...
For the electrochemical cell, \text{Mg(s)}\left|{\text{Mg}}^{\text{2+}} \left(\text{aq,1}\text{M}\right)\right|\left|{\text{Cu}}^{\text{2+}} \left(\text{aq,1}\text{M}\right)\right|\text{Cu}\left(\text{s}\right)standard emf of the cell is \text{2}\text{.70 V}\text{300 K}\text{.} Whenf{\text{Mg}}^{\text{2+}}\text{x M,}\text{2}\text{.67 V}\text{300 K}\text{.}value of\text{x}is ________.<br />
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(given,\dfrac{\text{F}}{\text{R}}{\text{=11500 K V}}^{- \text{1}} \text{,}where \text{F} isFaraday constant and \text{R} is the gas constants,\text{ln}\left(\text{10}\right)\text{=}\text{2}\text{.30} )
Correct answer
0
Step-by-step solution
^{\text{2+}} \left(\text{aq}\right) \to {\text{Mg}}^{\text{2+}} \left(\text{aq}\right)
{}_{}^{} _{}{}^{} {\text{Cu}}^{\text{2+}} {\text{E}}_{\text{cell}} _{\text{cell}}^{\text{o}} - \dfrac{}{} -\dfrac{\text{RT}}{}
-\dfrac{\text{R}\text{\times}\text{300}} \dfrac{}{}\text{\times}\dfrac{\text{F}}{}<br />\text{=}\dfrac{\text{0}\text{.03}\text{\times}\text{2}\text{\times}\text{11500}}{\text{300}\text{\times}\text{1}}
{}_{}^{} _{}{}^{} {\text{Cu}}^{\text{2+}} {\text{E}}_{\text{cell}} _{\text{cell}}^{\text{o}} - \dfrac{}{} -\dfrac{\text{RT}}{}
-\dfrac{\text{R}\text{\times}\text{300}} \dfrac{}{}\text{\times}\dfrac{\text{F}}{}<br />\text{=}\dfrac{\text{0}\text{.03}\text{\times}\text{2}\text{\times}\text{11500}}{\text{300}\text{\times}\text{1}}