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The conductance of 0 .0015 M aqueous solution of a weak monobasic acid was determined by using a conductivity cell consisting of platinized Pt electrodes. The distance between the electrodes is 120 cm with an area of cross-section of 1 cm 2 . The conductance of this solution was found to be 5 × 10 - 7 S . The pH of the solution is 4 . The value of limiting molar conductivity of this weak monobasic acid in aqueou

Correct answer

0

Step-by-step solution

For weak acid, H + = cα = c × ∧ m c ∧ m ∞ = c × k × 1000 c ∧ m ∞ = k × 1000 ∧ m ∞ = G × l a × 1000 ∧ m ∞ 10 - 4 = 5 × 10 - 7 120 1 × 1000 Z × 10 2   ⇒   Z = 6

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