Quantrex Quantrex AcademyJEE · NEET · NDA PYQs with solutions Open app
JEE Advanced 2016Paper 2
Exam
JEE Advanced
Year
2016
Paper
Paper 2
Subject
Chemistry
Chapter
Electrochemistry

JEE Advanced 2016 · Paper 2 · Chemistry · Electrochemistry

For the following electrochemical cell at 289 K, Pt( s )| H _ 2 (...

For the following electrochemical cell at 289 K,\text{289 K,}
Pt(s)∣H2(g,1bar)∣H+(aq,1M)∣∣M4+(aq.), M2+(aq.)∣Pt(s)\text{Pt}( \text{s} )| {H}_{2} ( \text{g}, 1\text{bar} ) |H^{+}( \text{aq}, 1\text{M} ) | | {\text{M}}^{4 +}( \text{aq} . ){\text{, M}}^{\text{2+}} ( \text{aq} . ) | \text{Pt} ( \text{s} )
Ecell=0.092V{E}_{cell} = 0.092V when [M2+(aq.)][M4+(aq.)]=10x\dfrac{\left[M^{2 +}\left(aq .\right)\right]}{\left[M^{4 +}\left(aq .\right)\right]} = {10}^{x}
Given: EM4+/M2+0=0.151V;2.303RTF=0.059{E}_{M^{4 +} / M^{2 +}}^{0} = 0.151V; 2.303\dfrac{RT}{F} = 0.059
The value of x\text{x} is -

Options

  1. A-2
  2. B-1
  3. C1
  4. D2

Correct answer

D. 2

Step-by-step solution

At anode : H2(g)⇌2H+(aq)+2e−{H}_{2}\left(g\right) ⇌ 2{H}^{+}\left(aq\right) + 2{e}^{-}
At cathode : M4+(aq)+2e−⇌M2+(aq){M}^{4 +}\left(aq\right) + 2{e}^{-} ⇌ {M}^{2 +}\left(aq\right)
Net cell reaction : H2(g)+M4+(aq)⇌2H+(aq)+M2+(aq){H}_{2}\left(g\right) + {M}^{4 +}\left(aq\right) ⇌ 2{H}^{+}\left(aq\right) + {M}^{2 +} ( aq )
Ecell=Ecell0−0.0592log[M2+][H+]2[M4+](PH2){E}_{cell} = {E}_{cell}^{0} - \dfrac{0.059}{2} log\dfrac{[ {M}^{2 +} ] {[ {H}^{+} ]}^{2}}{[ {M}^{4 +} ] ( {P}_{{H}_{2}} )}
Now, Ecell=(EM4+/M2+0−EH+/H20)−0.059n.log[H+]2[M2+]PH2.[M4+]{E}_{cell} = \left({E}_{{M}^{4 +} / {M}^{2 +}}^{0} - {E}_{{H}^{+} / {H}_{2}}^{0}\right) - \dfrac{0.059}{n} . log \dfrac{{\left[{H}^{+}\right]}^{2}\left[{M}^{2 +}\right]}{{P}_{{H}_{2}} . \left[{M}^{4 +}\right]}
0.092=(0.151−0)−0.0592.log12×[M2+]1×[M4+]0.092 = \left(0.151 - 0\right) - \dfrac{0.059}{2} . log \dfrac{{1}^{2} \times \left[{M}^{2 +}\right]}{1 \times \left[{M}^{4 +}\right]}
∴[M2+][M4+]=102⇒x=2∴ \dfrac{\left[{M}^{2 +}\right]}{\left[{M}^{4 +}\right]} = {10}^{2} ⇒ x = 2
Practice Electrochemistry on Quantrex Academy →

More from Electrochemistry

At 300 K, the molar conductivities of the aqueous solutions of three salts at two… JEE Advanced 2026Given at 298 K: E^ _ Fe^ 2+ /Fe = X Volt; E^ _ Fe^ 3+ /Fe = Y Volt. The E^ _ Fe^ 3+ /Fe^… JEE Main 2026For a general redox reaction Anode : Red_1 arrow Ox_1^ n_1^+ + n_1 e^- Cathode : Ox_2 +… JEE Main 2026Consider the following data. Electrolyte Λ^ ∘ _m (S cm ^2 mol ^ -1 ) BaCl_2 x_1 H_2SO_4… JEE Main 2026One half cell in a voltaic cell is constructed by dipping silver rod in AgNO_3 solution… JEE Main 2026At 298 K , the molar conductivity of x\% (w/w) MX solution (aqueous) is 123.5 S cm^2 mol^… JEE Main 2026An electrochemical cell, consist of the following two redox couples, M^ x+ (aq)/M(s) [E_… JEE Main 2026Consider the following two half-cell reactions along with the standard reduction… JEE Main 2026 Full Electrochemistry list All JEE Advanced PYQs