JEE Advanced2008ChemistryElectrochemistryActual
Electrolysis of dilute aq. NaCl solution was carried out by passing 10 ~mA current. The time required to liberate 0.01 mole of H ₂ gas at the cathode is (1 Faraday =96500 C mol ⁻¹ )
Options
- A9.65 10^4 ~s
- B19.3 10^4 ~s
- C28.95 10^4 ~s
- D38.6 10^4 ~s
Correct answer
B. 19.3 10^4 ~s
Step-by-step solution
2 H ₂ O +2 e⁻ H ₂+2 OH ⁻ For 0.01 mole of H ₂, 0.02 mole of electrons are consumed Charge required =0.02 96500 C =i t Time required = 0.02 96500 10 10⁻³ =19.3 10^4 ~s