Exam

JEE Advanced

Year

2025

Paper

Paper 1

Subject

Chemistry

Chapter

Haloalkanes and Haloarenes

JEE Advanced 2025 · Paper 1 · Chemistry · Haloalkanes and Haloarenes

The reaction sequence given below is carried out with 16 moles of X...

The reaction sequence given below is carried out with 16 moles of $\mathbf{X}$. The yield of the major product in each step is given below the product in parentheses. The amount (in grams)$of \mathbf{S}$ produced is ______ . $\text{ Use: Atomic mass (in amu): } \mathrm{H}=1, \mathrm{C}=12, \mathrm{O}=16, \mathrm{Br}=80$

Step-by-step solution

$$\begin{aligned} & \mathrm{M}=\left(\mathrm{C}_6 \mathrm{H}_4\right)_2\left(\mathrm{C}_6 \mathrm{H}_5\right)_2 \mathrm{C}_2 \mathrm{H}_4 \mathrm{O} \\ & =350 \end{aligned}$$ Weight of product of $S=350 \times 1 / 2=175 \mathrm{gm}$ Ans. * WES : Williamson ether synthesis