Correct statement(s) about the compounds P , Q and R is(are)

From the given reaction conditions:

$\text{Xe(g)} + 2\text{F}_2\text{(g)} \xrightarrow[\text{1 : 5 ratio}]{\text{873 K, 7 bar}} \text{XeF}_4$
Thus, $\textbf{P}$ is $\text{XeF}_4$.

$\text{XeF}_4 + \text{O}_2\text{F}_2 \xrightarrow{\text{143 K}} \text{XeF}_6 + \text{O}_2$
Thus, $\textbf{Q}$ is $\text{XeF}_6$.

$\text{XeF}_6 + 3\text{H}_2\text{O} \xrightarrow{\text{complete hydrolysis}} \text{XeO}_3 + 6\text{HF}$
Thus, $\textbf{R}$ is $\text{XeO}_3$.

Evaluating the given options:
(A) $\textbf{P}$ ($\text{XeF}_4$) has $8$ valence electrons on the central Xe atom. It forms $4$ single bonds with F, leaving $4$ electrons which form $2$ lone pairs. This statement is correct.

(B) $\textbf{Q}$ ($\text{XeF}_6$) has $6$ bond pairs and $1$ lone pair on the central Xe atom. Its geometry is distorted octahedral, not perfect octahedral. This statement is incorrect.

(C) $\textbf{Q}$ ($\text{XeF}_6$) is a strong fluorinating agent. This statement is correct.

(D) $\textbf{R}$ ($\text{XeO}_3$) has $3$ double bonds and $1$ lone pair on the central Xe atom. Its molecular structure is trigonal pyramidal. This statement is correct.

Answer: $\textbf{P}$ has two lone pairs of electrons on the central atom.; $\textbf{Q}$ can act as a fluorinating agent.; The molecular structure of $\textbf{R}$ is trigonal pyramidal.