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JEE Advanced 2012Paper 2
Exam
JEE Advanced
Year
2012
Paper
Paper 2
Subject
Chemistry
Chapter
Redox Reactions

JEE Advanced 2012 · Paper 2 · Chemistry · Redox Reactions

Bleaching powder and bleach solution are produced on a large scale...

Bleaching powder and bleach solution are produced on a large scale and used in several household products. The effectiveness of bleach solution is often measured by iodometry. Question: 25 mL25 \mathrm{~mL} of household solution was mixed with 30 mL30 \mathrm{~mL} of 0.500.50 M KI and 10 mL10 \mathrm{~mL} of 4 N4 \mathrm{~N} acetic acid. In the titration of the liberated iodine, 48 mL48 \mathrm{~mL} of 0.25 N Na2 S2O30.25 \mathrm{~N~} \mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3} was used to reach the end point. The molarity of the household bleach solution is

Options

  1. A0.48M0.48 \mathrm{M}
  2. B0.96M0.96 \mathrm{M}
  3. C0.24M0.24 \mathrm{M}
  4. D0.024M0.024 \mathrm{M}

Correct answer

C. 0.24M0.24 \mathrm{M}

Step-by-step solution

Bleach +2KI⟶+2 \mathrm{KI} \longrightarrow\mathrm{I}2+_{2}+ Products I2+2Na2 S2O3⟶Na2 S4O6+2NaI\mathrm{I}_{2}+2 \mathrm{Na}_{2} \mathrm{~S}_{2} \mathrm{O}_{3} \longrightarrow \mathrm{Na}_{2} \mathrm{~S}_{4} \mathrm{O}_{6}+2 \mathrm{NaI} Number of millimole of hypo =0.25×48=2×=0.25 \times 48=2 \times millimole of I2∴\mathrm{I}_{2}\therefore Number of millimole of I2=0.25×482=6\mathrm{I}_{2}=\frac{0.25 \times 48}{2}=6 millimole of I2=\mathrm{I}_{2}= millimole of bleach Molarity of bleaching solution = Millimoles of bleach  Vol.(in mL ) of bleach =625=0.24=\frac{\text{ Millimoles of bleach }}{\text{ Vol.(in } \mathrm{mL} \text{ ) of bleach }}=\frac{6}{25}=0.24
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