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JEE Main 201212 MayOnline
Exam
JEE Main
Year
2012
Date
12 May
Mode
Online
Subject
Chemistry
Chapter
Redox Reactions

JEE Main 2012 · 12 May · Online · Chemistry · Redox Reactions

In the following balanced reaction, values of X, Y and Z...

In the following balanced reaction, In the following balanced reaction, values of X, Y and Z respectively are
values of X,YX, Y and ZZ respectively are

Options

  1. A2,5,16
  2. B8,2,58,2,5
  3. C5,2,165,2,16
  4. D5,8,45,8,4

Correct answer

A. 2,5,16

Step-by-step solution

XMnO4−+YC2O4−+ZH+⇋X \mathrm{MnO}_4^{-}+Y \mathrm{C}_2 \mathrm{O}_4^{-}+Z \mathrm{H}^{+} \leftrightharpoons X Mn+++2YCO2+Z2H2O\mathrm{Mn}^{++}+2 Y \mathrm{CO}_{2}+\frac{Z}{2} \mathrm{H}_{2} \mathrm{O} First half reaction MnO4−⟶Mn++OnbalancingMnO4\mathrm{MnO}_{4}^{-} \longrightarrow \mathrm{Mn}^{++}On balancing \mathrm{MnO}_{4}^{-}+8 H++5e−\mathrm{H}^{+}+5 \mathrm{e}^{-} \longrightarrow Mn+++4H2O\mathrm{Mn}^{++}+4 \mathrm{H}_{2} \mathrm{O} Second half reaction \mathrm{C} }_{2} \mathrm{O}_{4}^{-} \longrightarrow 2 \mathrm{CO}_{2} On balancing C2O\mathrm{C}_{2} \mathrm{O}_{{4}}−⟶2CO2+^{-} \longrightarrow 2 \mathrm{CO}_{2}+2 e−Onmultiplyingeqn.(ii)by5and\mathrm{e}^{-}On multiplying eqn. (ii) by 5 and(iv) by 2 and then adding we get 2MnO4−+5C2O4−−+16H+⟶2Mn+++10CO2+8H2O\begin{aligned} & 2\mathrm{MnO}_{4}^{-}+5 \mathrm{C}_{2} \mathrm{O}_{4}^{--}+16 \mathrm{H}^{+} \longrightarrow \\ & 2 \mathrm{Mn}^{++}+10 \mathrm{CO}_{2}+8 \mathrm{H}_{2} \mathrm{O} \end{aligned}
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