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JEE Advanced 2007Paper 2
Exam
JEE Advanced
Year
2007
Paper
Paper 2
Subject
Chemistry
Chapter
Redox Reactions

JEE Advanced 2007 · Paper 2 · Chemistry · Redox Reactions

Paragraph: Redox reaction play a pivotal role in chemistry and...

Paragraph: Redox reaction play a pivotal role in chemistry and biology. The values of standard redox potential (E∘)\left(E^{{}^{\circ}}\right) of two half-cell reactions decide which way the reaction is expected to proceed. A simple example is a Daniel cell in which zinc goes into solution and copper gets deposited. Given below are a set of half-cell reactions (acidic medium) along with their E∘(VE^{{}^{\circ}}(V with respect to normal hydrogen electrode) values. Using this data obtain the correct explanations to Questions 14-19. I2+2e−⟶2I−E∘=0.54Cl2+2e−⟶2Cl−E∘=1.36Mn3++e−⟶Mn2+E∘=1.50Fe3++e−⟶Fe2+E∘=0.77O2+4H++4e−⟶2H2OE∘=1.23\begin{array}{cl}\mathrm{I}_{2}+2 e^{-} \longrightarrow 2 \mathrm{I}^{-}& E^{{}^{\circ}}=0.54 \\ \mathrm{Cl}_{2}+2 e^{-} \longrightarrow 2 \mathrm{Cl}^{-}& E^{{}^{\circ}}=1.36 \\ \mathrm{Mn}^{3+}+e^{-} \longrightarrow \mathrm{Mn}^{2+}& E^{{}^{\circ}}=1.50 \\ \mathrm{Fe}^{3+}+e^{-} \longrightarrow \mathrm{Fe}^{2+}& E^{{}^{\circ}}=0.77 \\ \mathrm{O}_{2}+4 \mathrm{H}^{+}+4 e^{-} \longrightarrow 2 \mathrm{H}_{2}\mathrm{O}& E^{{}^{\circ}}=1.23 \end{array} Question: Among the following, identify the correct statement

Options

  1. AChloride ion is oxidised by O2\mathrm{O}_2
  2. BFe2+\mathrm{Fe}^{2+} is oxidised by iodine
  3. CIodide ion is oxidised by chlorine
  4. DMn2+\mathrm{Mn}^{2+} is oxidised by chlorine

Correct answer

C. Iodide ion is oxidised by chlorine

Step-by-step solution

22\mathrm{I}−+Cl2⟶^{-}+\mathrm{Cl}_2 \longrightarrow\mathrm{I}_2+2 \mathrm{Cl}^{-} E_{\text{cell }^{\circ}=1.36-0.54=0.82 \mathrm{ V} E_{\text{cell } }^{\circ} is +ve+v e cell reactions is feasible.
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