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JEE Advanced 2015Paper 1
Exam
JEE Advanced
Year
2015
Paper
Paper 1
Subject
Chemistry
Chapter
Solutions

JEE Advanced 2015 · Paper 1 · Chemistry · Solutions

If the freezing point of a 0.01 molal aqueous solution of a cobalt...

If the freezing point of a 0.01 molal aqueous solution of a cobalt (III) chloride-ammonia complex (which behaves as a strong electrolyte) is −0.0558oC- {0.0558}^{o}C , the number of chloride(s) in the coordination sphere of the complex is
[Kfofwater=1.86Kkgmol−1][ {K}_{f}ofwater = 1.86Kkgmo{l}^{- 1} ]

Correct answer

1

Step-by-step solution

∆ {T}_{f} = {K}_{f} \times i \times m<br/><br />0.0558 = 1.86 \times i \times 0.01<br/><br />i = 3<br/>Givencomplexbehavesasastrongelectrolyte<br/><br />Given complex behaves as a strong electrolyte<br />\alpha = 100%<br/>n=3(no.ofparticlesgivenbycomplex)<br/><br />n = 3 (no. of particles given by complex)<br />∴complexis[Co(NH3)5Cl]Cl2complex is \left[Co{\left(N{H}_{3}\right)}_{5}Cl\right]C{l}_{2}
no. of Cl−C{l}^{-} ions in the co-ordination sphere of the complex = 1
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