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The freezing point (in ^ C ) of solution containing 0.1 ~g of K ₃ [ Fe ( CN )₆ ] (molecular weight 329 ) in 100 ~g of water (K_f=1.86 ~K ~kg ~mol ⁻¹ ) is

Options

  1. A-2.3 10⁻²
  2. B-5.7 10⁻²
  3. C-5.7 10⁻³
  4. D-1.2 10⁻²

Correct answer

A. -2.3 10⁻²

Step-by-step solution

vant Hoff's factor (i)=4 3 ~K ⁺+ [ Fe ( CN )₆ ]³⁻ Molality = 0.1 329 1000 100 = 1 329 - T_f=i K_f m=4 1.86 1 329 =2.3 10⁻² T_f=-2.3 10⁻² ^ C (As freezing point of water is 0^ C )

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