JEE Advanced2009ChemistrySolutionsActual
The Henry's law constant for the solubility of N ₂ gas in water at 298 ~K is 1.0 105 ~atm . The mole fraction of N ₂ in air is 0.8 . The number of moles of N ₂ from air dissolved in 10 moles of water of 298 ~K and 5 ~atm pressure is
Options
- A4 10⁻⁴
- B4.0 10⁻⁵
- C5.0 10⁻⁴
- D4.0 10⁻⁶
Correct answer
A. 4 10⁻⁴
Step-by-step solution
P_ N ₂ =K_ H mole-fraction ( N ₂ ) mole-fraction N ₂ 1 10^5 0.8 5=4 10⁻⁵ ~mol ⁻¹ In 10 mole solubility in 4 10⁻⁴ .