Not considering the electronic spin, the degeneracy of the second...

Energy order of orbitals of H is decided by only principle quantum number (n) while energy order of ${H}^{-}$ is decided by $( n + l )$ rule:
Electronic configuration of $′{H}^{-}′$ is $- 1{s}^{2}$ its energy order is decided by $n + l$ rule.
${H}^{-} = 1{s}^{2}2{s}^{0}2{p}^{0}$
Its ${2}^{nd}$ excited state is 2p
And degeneracy $2pis3$.