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JEE Advanced2012ChemistryStructure of AtomActual

The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is [a₀ . is Bohr radius ] :

Options

  1. Ah² 4 ² m a₀²
  2. Bh² 16 ² m a₀²
  3. Ch² 32 ² m a₀²
  4. Dh² 64 ² m a₀²

Correct answer

C. h² 32 ² m a₀²

Step-by-step solution

As per Bohr's postulate, array l m v r= n h 2 So, v= n h 2 m r KE = 1 2 m v² So, KE = 1 2 m ( n h 2 m r )² array Since, r= a_ o n² z So, for 2^ nd Bohr orbit array l r= a_ o 2² 1 =4 a_ o KE = 1 2 m ( 2² h² 4 ² m² (4 a_ o )² )= h² 32 ² m a_ o ² array

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