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JEE Advanced 2008Paper 1
Exam
JEE Advanced
Year
2008
Paper
Paper 1
Subject
Chemistry
Chapter
Structure of Atom

JEE Advanced 2008 · Paper 1 · Chemistry · Structure of Atom

Statement 1 The plot of atomic number ( Y -axis) versus number of...

Statement 1 The plot of atomic number ( YY-axis) versus number of neutrons ( xx-axis) for stable nuclei shows a curvature towards XX-axis from the line of 45∘45^{\circ} slope as the atomic number is increased. Statement 2 Proton-proton electrostatic repulsions begin to overcome attractive forces involving protons and neutrons in heavier nuclides.Statement 1 The plot of atomic number ( Y -axis) versus number of neutrons ( x -axis) for stable nuclei shows a

Options

  1. AStatement 1 is true, Statement 2 is true, Statement 2 is a correct explanation for Statement 1.
  2. BStatement 1 is true, Statement 2 is true, Statement 2 is not a correct explanation for Statement 1.
  3. CStatement 1 is true, Statement 2 is false.
  4. DStatement 1 is false, Statement 2 is true

Correct answer

A. Statement 1 is true, Statement 2 is true, Statement 2 is a correct explanation for Statement 1.

Step-by-step solution

The stability relationship can be represented by a line with a slope of 45∘45^{\circ}, i.e. the maximum stability is attained, when N=ZN=Z. Right or the curve a radioactive nuclide would be neutron rich and would decay be β\beta-emission to produce a daughter nucleus with a lower np\frac{n}{p} ratio. For heavier nuclides, p−pp-p repulsions start to offset the attractive forces and an excess of neutrons over protons, is required for stability Statement 1 The plot of atomic number ( Y -axis) versus number of neutrons ( x -axis) for stable nuclei shows a
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