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JEE Advanced2026ChemistryThermodynamics (C)Actual

List-I contains various physical/chemical processes, and List-II contains combinations of changes in enthalpy ( H ) and entropy ( S ). Match each entry in List-I to the appropriate entry in List-II, and choose the correct option. List-I List-II (P) Physisorption (1) H > 0 and S > 0 (Q) Diamond Graphite (2) H (R) Denaturation of protein (3) H (S) Propene Cyclopropane (4) H > 0 and S (5) H 0

Options

  1. AP 2; Q 3; R 5; S 4
  2. BP 4; Q 3; R 5; S 1
  3. CP 2; Q 5; R 1; S 4
  4. DP 2; Q 5; R 1; S 3

Correct answer

C. P 2; Q 5; R 1; S 4

Step-by-step solution

(P) Physisorption is an exothermic process because attractive forces are formed between the adsorbate and the adsorbent, so H (Q) Diamond Graphite is an exothermic process because graphite is the thermodynamically more stable allotrope of carbon at standard conditions ( H 0 ). This matches (5). (R) Denaturation of protein involves the breaking of hydrogen bonds and the unfolding of its specific 3D structure into a more random coil. Breaking these interactions requires energy ( H > 0 ) and the unfolding increases ra

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