JEE Advanced 2026Paper 1
- Exam
- JEE Advanced
- Year
- 2026
- Paper
- Paper 1
- Subject
- Chemistry
- Chapter
- Thermodynamics (C)
JEE Advanced 2026 · Paper 1 · Chemistry · Thermodynamics (C)
List-I contains various physical/chemical processes, and List-II...
List-I contains various physical/chemical processes, and List-II contains combinations of changes in enthalpy () and entropy (). Match each entry in List-I to the appropriate entry in List-II, and choose the correct option.
| List-I | List-II |
|---|---|
| (P) Physisorption | (1) and |
| (Q) Diamond Graphite | (2) and |
| (R) Denaturation of protein | (3) and |
| (S) Propene Cyclopropane | (4) and |
| (5) and |
Options
- AP 2; Q 3; R 5; S 4
- BP 4; Q 3; R 5; S 1
- CP 2; Q 5; R 1; S 4
- DP 2; Q 5; R 1; S 3
Correct answer
C. P 2; Q 5; R 1; S 4
Step-by-step solution
(P) Physisorption is an exothermic process because attractive forces are formed between the adsorbate and the adsorbent, so . The gas molecules are restricted on the solid surface, decreasing randomness, so . This matches (2).
(Q) Diamond Graphite is an exothermic process because graphite is the thermodynamically more stable allotrope of carbon at standard conditions (). Graphite has a layered structure and is less dense, so it has higher entropy than the rigid 3D network of diamond (). This matches (5).
(R) Denaturation of protein involves the breaking of hydrogen bonds and the unfolding of its specific 3D structure into a more random coil. Breaking these interactions requires energy () and the unfolding increases randomness (). This matches (1).
(S) Propene Cyclopropane is an endothermic process because cyclopropane has significant ring strain compared to the open-chain propene, making it less stable (). The formation of a rigid ring restricts the degrees of freedom (such as rotation around single bonds), decreasing entropy (). This matches (4).
Thus, P 2, Q 5, R 1, S 4.
Answer: P 2; Q 5; R 1; S 4
(Q) Diamond Graphite is an exothermic process because graphite is the thermodynamically more stable allotrope of carbon at standard conditions (). Graphite has a layered structure and is less dense, so it has higher entropy than the rigid 3D network of diamond (). This matches (5).
(R) Denaturation of protein involves the breaking of hydrogen bonds and the unfolding of its specific 3D structure into a more random coil. Breaking these interactions requires energy () and the unfolding increases randomness (). This matches (1).
(S) Propene Cyclopropane is an endothermic process because cyclopropane has significant ring strain compared to the open-chain propene, making it less stable (). The formation of a rigid ring restricts the degrees of freedom (such as rotation around single bonds), decreasing entropy (). This matches (4).
Thus, P 2, Q 5, R 1, S 4.
Answer: P 2; Q 5; R 1; S 4