Match the statements of Column I with these in Column II. [Note : Here z takes values in the complex plane and Im (z) and Re (z) denote respectively, the imaginary part and the real part of z ]

Step-by-step solution

(A) z is equidistant from the points i|z| and -i|z| , whose perpendicular bisector is Im (z)=0 . (B) Sum of distance of z from (4,0) and (-4,0) is a constant 10 , hence locus of z is ellipse with semi-major axis 5 and focus at ( 4,0), a e=4 . e= 4 5 (C) |z| |w|+ | 1 w |= 5 2 < 3 (D) |z| |w|+ | 1 w |=2 Re (z) |z| 2