JEE Advanced 2017Paper 1
- Exam
- JEE Advanced
- Year
- 2017
- Paper
- Paper 1
- Subject
- Mathematics
- Chapter
- Definite Integration
JEE Advanced 2017 · Paper 1 · Mathematics · Definite Integration
Let f: ℝ → ℝ be a differentiable function such that f(0) = 0,...
Let f\left(0\right) = 0, f\left(\dfrac{\pi}{2}\right) = 3{f}^{′}\left(0\right) = 1 .g\left(x\right) = {∫}_{x}^{\dfrac{\pi}{2}}\left[{f}^{′}\left(t\right)cosect - \cot t \cos ectf\left(t\right)\right]dtx \in then
Correct answer
2