JEE Advanced 2014Paper 2
- Exam
- JEE Advanced
- Year
- 2014
- Paper
- Paper 2
- Subject
- Mathematics
- Chapter
- Definite Integration
JEE Advanced 2014 · Paper 2 · Mathematics · Definite Integration
Match the following. List – I List – II (A) The number of...
Match the following.
| List – I | List – II | ||
| (A) | The number of polynomials f(x) with non – negative integer coefficients of degree satisfying f(0) =0 and | (P) | 8 |
| (B) | The number of point in the interval at which attains its maximum value, is | (Q) | 2 |
| (C) | equals | (R) | 4 |
| (D) | (S) | 0 |
Options
- Aa-r;b-p;c-s;d-q;
- Ba-q;b-r;c-p;d-s;
- Ca-p;b-r;c-q;d-s;
- Da-q;b-p;c-s;d-r;
Correct answer
B. a-q;b-r;c-p;d-s;
Step-by-step solution
\left(P\right)f\left(x\right) = a{x}^{2} + bx, \mathop{∫}_{0}^{1}f\left(x\right)dx = 1⇒ 2a + 3b = 6⇒ \left(a, b\right) ≡ \left(0, 2\right)and\left(3, 0\right)
For maximum value,
as
\left(R\right)\mathop{∫}_{0}^{2}\left(\dfrac{3{x}^{2}}{1 + {e}^{x}} + \dfrac{3{x}^{2}}{1 + {e}^{- x}}\right)dx =\mathop{∫}_{0}^{2}3{x}^{2}dx = 8 as it is an odd function.
For maximum value,
as
\left(R\right)\mathop{∫}_{0}^{2}\left(\dfrac{3{x}^{2}}{1 + {e}^{x}} + \dfrac{3{x}^{2}}{1 + {e}^{- x}}\right)dx =\mathop{∫}_{0}^{2}3{x}^{2}dx = 8 as it is an odd function.